2x^2+8x-1144=0

Solution for 2x^2+8x-1144=0 equation:

2x^2+8x-1144=0

a = 2; b = 8; c = -1144;
Δ = b2-4ac
Δ = 82-4·2·(-1144)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-96}{2*2}=\frac{-104}{4}
=-26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+96}{2*2}=\frac{88}{4}
=22
$